11-08-2025, 08:01 PM (This post was last modified: 11-08-2025, 08:15 PM by sparky2026.)
Hi my friends
I share with you as other people do it, results, theorical and practical facts let me build devices based in this principle
Harmonics are free energy, reactive energy wasted, not used, but in common engineering is stated are trash, an undesired situation can be destroyed by filters
The Parseval theorem is used for show all energy from harmonics is the same energy of the entire signal, but it sums all squares of each harmonic, however if we sum all amplitudes we get overunity and infinite energy if we process all infinite harmonics
Quantum Mechanics says one quanta of a signal at f frequency have an energy
E = h * f
But the n harmonic have an energy
E= n * h * f
So energy of all harmonics or the infinite harmonics have infinite energy showing there is some wrong in the Parseval theorem
The calculus of Fourier series show the harmonics of a square wave don't decay or decay slow if the duty cycle is too low, let's say 2% or 1%
My method is as follows:
* Generate a square wave of too low duty cycle
* Add filters, bandpass filters tuned to first, second, third or more harmonics
* The AC output of each filter will be rectified
* All the rectifier are series connected, so the sum of all rectified will go to the load
In ideal conditions you can proof
COP = n
The following test is for audio frequency and I've used a coil in series with a capacitor as bandpass filter
5 harmonics are processed
as shown
The power source was 12VDC , 1A at 1% duty cycle
Input power 12 * 1 /100 = 0.12W
Load resistance = 1000 ohms
Flat voltage = 24 VDC
Output power = 0.58W
COP = 4.83
Is near to the theory must be 5 for 5 processing harmonics
There is pictures for measurements and the circuit used
thank you for the idea and realization. So where do you think the extra power comes from? How are you measuring the input that you are so sure it only takes the 1A and not more from the power source for each pulse?
Parseval theorem may not even say much about the harmonics or real signals, it is used mostly to prove that signals power is the same as the squared spectrums power. However in Fourier transform you have negative time and work with complex conjugates. Whatever that means physically Guests cannot see images in the messages. Please register at the forum by clicking here to see images.
What do you use for the bandpass filters? What Q do the filters have?
I hope I don't ask too rough questions, I like the idea but I have questions Guests cannot see images in the messages. Please register at the forum by clicking here to see images.
Forgot to add, the reason I am asking about the Q of the filters, or in this case it looks like LC resonators is because I am now researching resonance as a gain mechanism and it might as well be that the overunity comes from the LC resonators.
11-12-2025, 06:07 AM (This post was last modified: 11-12-2025, 06:30 AM by Dexter2025.)
(11-09-2025, 10:06 AM)kloakez Wrote: Hi sparky2026,
thank you for the idea and realization. So where do you think the extra power comes from? How are you measuring the input that you are so sure it only takes the 1A and not more from the power source for each pulse?
Parseval theorem may not even say much about the harmonics or real signals, it is used mostly to prove that signals power is the same as the squared spectrums power. However in Fourier transform you have negative time and work with complex conjugates. Whatever that means physically Guests cannot see images in the messages. Please register at the forum by clicking here to see images.
What do you use for the bandpass filters? What Q do the filters have?
I hope I don't ask too rough questions, I like the idea but I have questions Guests cannot see images in the messages. Please register at the forum by clicking here to see images.
***************************************
Planck states
E = h * f
So energy is frequency, but frequency is time
So energy becomes from time, here time is converted to energy
The input power measurement method is classic
A 0.1 resistor you get the current from the DC power source is powered the square wave input power and 5hen captured by an Excel form and multiply the power source DC voltage by the current data and get the mean value is the active input power in watts
The pass band filter was a capacitor in series with a coil, as losses are low my Q was over 100
The next step was get kilowatts at COP=5 by using as input power pulse an audio power amplifier and ready made crossovers from the market
(11-08-2025, 08:01 PM)sparky2026 Wrote: The next step was get real power, kilowatts output
I was using this 4kw car audio amplifier
Hi my friends
I share with you as other people do it, results, theorical and practical facts let me build devices based in this principle
Harmonics are free energy, reactive energy wasted, not used, but in common engineering is stated are trash, an undesired situation can be destroyed by filters
The Parseval theorem is used for show all energy from harmonics is the same energy of the entire signal, but it sums all squares of each harmonic, however if we sum all amplitudes we get overunity and infinite energy if we process all infinite harmonics
Quantum Mechanics says one quanta of a signal at f frequency have an energy
E = h * f
But the n harmonic have an energy
E= n * h * f
So energy of all harmonics or the infinite harmonics have infinite energy showing there is some wrong in the Parseval theorem
The calculus of Fourier series show the harmonics of a square wave don't decay or decay slow if the duty cycle is too low, let's say 2% or 1%
My method is as follows:
* Generate a square wave of too low duty cycle
* Add filters, bandpass filters tuned to first, second, third or more harmonics
* The AC output of each filter will be rectified
* All the rectifier are series connected, so the sum of all rectified will go to the load
In ideal conditions you can proof
COP = n
The following test is for audio frequency and I've used a coil in series with a capacitor as bandpass filter
5 harmonics are processed
as shown
The power source was 12VDC , 1A at 1% duty cycle
Input power 12 * 1 /100 = 0.12W
Load resistance = 1000 ohms
Flat voltage = 24 VDC
Output power = 0.58W
COP = 4.83
Is near to the theory must be 5 for 5 processing harmonics
There is pictures for measurements and the circuit used
(11-15-2025, 09:49 AM)Backtorque Wrote: What's even the definition of reactive energy?
Think of a coil (or a capacitor) like a springy trampoline.
The battery “throws” a tennis ball (electric energy) at the trampoline.
The trampoline pushes the ball back.
The ball comes back toward the battery.
Then the battery throws it again.
The ball keeps bouncing.
That back-and-forth motion is reactive energy.
The key idea:
Real energy gets used up to do work (like powering a light bulb).
Reactive energy just moves back and forth without getting used up.
Free-energy researchers ask questions like:
Can we use some of the bouncing energy without stopping the bounce?
Or can we use the energy in a way that actually helps the bounce get bigger, instead of slowing it down?
Obviously it is more technical than that- but that should portray the general idea
The oscillating emf might be used without stopping the bounce by getting an oscillation in opposing partnered output coils or by using it in a single wire fashion like Avramenko and Don Smith by connecting one end of a tesla coil through a capacitor to the earth. Didn't Kapanadze do the same?
What's the definition of magnetic resonance? Getting the bounce bigger?
(11-08-2025, 08:01 PM)sparky2026 Wrote: This is the power filters or crossovers I was using for multiply the 4kw input to 20 kw output by using 5 filters like the other low power experiment
As load I was using 10 heaters of 2kw each
*****************************************************
I share with you as other people do it, results, theorical and practical facts let me build devices based in this principle
Harmonics are free energy, reactive energy wasted, not used, but in common engineering is stated are trash, an undesired situation can be destroyed by filters
The Parseval theorem is used for show all energy from harmonics is the same energy of the entire signal, but it sums all squares of each harmonic, however if we sum all amplitudes we get overunity and infinite energy if we process all infinite harmonics
Quantum Mechanics says one quanta of a signal at f frequency have an energy
E = h * f
But the n harmonic have an energy
E= n * h * f
So energy of all harmonics or the infinite harmonics have infinite energy showing there is some wrong in the Parseval theorem
The calculus of Fourier series show the harmonics of a square wave don't decay or decay slow if the duty cycle is too low, let's say 2% or 1%
My method is as follows:
* Generate a square wave of too low duty cycle
* Add filters, bandpass filters tuned to first, second, third or more harmonics
* The AC output of each filter will be rectified
* All the rectifier are series connected, so the sum of all rectified will go to the load
In ideal conditions you can proof
COP = n
The following test is for audio frequency and I've used a coil in series with a capacitor as bandpass filter
5 harmonics are processed
as shown
The power source was 12VDC , 1A at 1% duty cycle
Input power 12 * 1 /100 = 0.12W
Load resistance = 1000 ohms
Flat voltage = 24 VDC
Output power = 0.58W
COP = 4.83
Is near to the theory must be 5 for 5 processing harmonics
There is pictures for measurements and the circuit used
