Figuera patent isn’t just about "adding a fixed value per segment" — it’s about dynamically distributing current between the two opposing primary coils N and S such that:
? The Figuera Principle:
? What That Means Electrically:
? Resistor Chain Logic (Part G)
The resistor network is like a voltage divider where:
As you see voltage driving this coils is 24V and 30 hz rpm see outcome by yourself
Blue is primary voltage across primary coils Energy stored
The same in the other coil
It is important for me to find fine balance between the resistors and turns of příměry coil
I’m using in this set up 1.6 mm wire with 960 turns - core is 70mmx 70mm x150 mm soft iron
✅ Corrected Resistor Plan:
Instead of one resistor per commutator contact, Figuera used a chain of resistors, like this:
16 - 1 0%
1 - 2 25%
2 - 3 67%
3 - 4 250%
4 - 5 250%
5 - 7 67%
7 - 8 25%
8 - 9 0%
TIMING OF CHANGE OVER IS ON SEGMENT 4-5 THEN SPARKING ON COMUTATOR IS MINIMAL
and this is what confuses us all
then add this diagram
+DC
│
┌────┴────┐
│ │
┌────▼────┐ ┌──▼────┐
│ COM #2/1 │ │ COM #2/2│ ← Direction Switch (25 Hz) on the same shaft
│ (Polarity)│ │
└────┬────┘ └──┬─────┘
│ │
▼ ▼
┌────────┐ ┌────────┐
│Primary N│ │Primary S│
└───┬─────┘ └────┬───┘
│ │
└──┬───────┬──┘
▼ ▼
┌──────────────┐
│ COM #1 │ ← 8-Segment Resistor Commutator
│ (Segments 1–8│
└──────────────┘
│
minus V
⬍ Secondary Coil ⬍
(Fixed in air gap between N and S)
(Sees 50 Hz alternating field)
Primary N: /¯¯¯¯¯\ /¯¯¯¯¯\
Primary S: \_____/ \_____
< 20 ms > < 20 ms > (25 Hz switching)
Resistor waveform: ramp ↑ then ↓ (half-sine)
Segment 4-5 → 12-13
Switch happens at Segment 4–5 and 12 - 13 ⇨ minimal current of wave ⇨ seamless handoff
Output from secondary is perfect sine in 50 or 60Hz
I hope that this will help
I have tried many versions and this one with split commutator is working the best , not only is all happening much slower but each primary has time to absorb energy from other via magnetic linking North attracts South and South attracts North
Lasco
? The Figuera Principle:
- The sum of currents through the two opposing primaries is kept constant but 20ms apart
- The distribution of that current is shifted suddenly from one side to the other, via a second commutator
? What That Means Electrically:
- Imagine the total current = constant (say, 10 A)
- N:
- Coil N = 10 A, Coil S = 0 A (16 - 1)
- Coil N = 10 A, Coil S = 0 A (16 - 1)
- Mid-cycle:
- Coil N = 1 A, Coil S = 0 A (4 - 5) (12-13)
- Coil N = 1 A, Coil S = 0 A (4 - 5) (12-13)
- Coil N = 0 A, Coil S = 1 A (5 - 6) (13-14
- Coil N = 0 A, Coil S = 1 A (5 - 6) (13-14
? Resistor Chain Logic (Part G)
The resistor network is like a voltage divider where:
- Each segment taps off a different voltage
- A rotating brush connects to one tap at a time
- This gradually increases one coil’s current while decreasing the other’s
- This line above is incorrect and I apologise for it
- This gradually increases one side coil’s current to maximum (1-16) or (8-9) and as commutator progresses it reduces coil’s current to minimum ( contacts 4 and 13) in minimum current situation other commutator changes the contact to other coil’s)
- Small switching commutator is drawn as small square with terminals coming from S coils and N coils
- Energy stored in the steel core complement full sinus wave on each coil without commutator going full circle therefore 30 hz rotation will produce 60 hz
- Please observe rize of voltage on primary coils and the waveform
- This phenomena can occur only if steel core is large enough and current is correctly adjusted with correct resistors
As you see voltage driving this coils is 24V and 30 hz rpm see outcome by yourself
Blue is primary voltage across primary coils Energy stored
The same in the other coil
It is important for me to find fine balance between the resistors and turns of příměry coil
I’m using in this set up 1.6 mm wire with 960 turns - core is 70mmx 70mm x150 mm soft iron
✅ Corrected Resistor Plan:
Instead of one resistor per commutator contact, Figuera used a chain of resistors, like this:
Code:
-V -----[R1]----[R2]---[R3]--[R4]---[R5]---[R6]---[R7]---
| | | | | | |
Tap1 Tap2 Tap3 ... Tap5 Tap7 Tap8 → rotating brush- Tap1 = full current to Coil N, none to Coil S
- Tap5 = balanced in resistance best position for primary changeover
- Tap8 = reversed: full current to Coil S, none to Coil N
16 - 1 0%
1 - 2 25%
2 - 3 67%
3 - 4 250%
4 - 5 250%
5 - 7 67%
7 - 8 25%
8 - 9 0%
TIMING OF CHANGE OVER IS ON SEGMENT 4-5 THEN SPARKING ON COMUTATOR IS MINIMAL
and this is what confuses us all
then add this diagram
+DC
│
┌────┴────┐
│ │
┌────▼────┐ ┌──▼────┐
│ COM #2/1 │ │ COM #2/2│ ← Direction Switch (25 Hz) on the same shaft
│ (Polarity)│ │
└────┬────┘ └──┬─────┘
│ │
▼ ▼
┌────────┐ ┌────────┐
│Primary N│ │Primary S│
└───┬─────┘ └────┬───┘
│ │
└──┬───────┬──┘
▼ ▼
┌──────────────┐
│ COM #1 │ ← 8-Segment Resistor Commutator
│ (Segments 1–8│
└──────────────┘
│
minus V
⬍ Secondary Coil ⬍
(Fixed in air gap between N and S)
(Sees 50 Hz alternating field)
- CHANGEOVER FROM PRIMARY "N" TO PRIMARY "S" must be lined on the same shaft on 4-5 segment
Primary N: /¯¯¯¯¯\ /¯¯¯¯¯\
Primary S: \_____/ \_____
< 20 ms > < 20 ms > (25 Hz switching)
Resistor waveform: ramp ↑ then ↓ (half-sine)
Segment 4-5 → 12-13
Switch happens at Segment 4–5 and 12 - 13 ⇨ minimal current of wave ⇨ seamless handoff
Output from secondary is perfect sine in 50 or 60Hz
I hope that this will help
I have tried many versions and this one with split commutator is working the best , not only is all happening much slower but each primary has time to absorb energy from other via magnetic linking North attracts South and South attracts North
Lasco

